5a^2-5=10a

Solution for 5a^2-5=10a equation:

5a^2-5=10a

We move all terms to the left:

5a^2-5-(10a)=0

a = 5; b = -10; c = -5;
Δ = b2-4ac
Δ = -102-4·5·(-5)
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10\sqrt{2}}{2*5}=\frac{10-10\sqrt{2}}{10}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10\sqrt{2}}{2*5}=\frac{10+10\sqrt{2}}{10}
$